Electronics Calculator

Series Capacitor Calculator

Calculate the equivalent capacitance of capacitors connected in series. Enter multiple capacitor values to calculate the total capacitance, common charge, voltage across each capacitor and stored energy.

Series Capacitor Inputs


V
Series capacitor network
C1 C2 Vs Same charge magnitude on each ideal series capacitor
Series capacitor rule
The same charge magnitude flows onto each capacitor, while the applied voltage divides between the capacitors.
Equivalent Capacitance
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Total Charge
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Applied Voltage
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Total Stored Energy
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Capacitor Count
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Capacitor Voltage Distribution

Capacitor Capacitance Charge Voltage Energy Voltage Share
Enter capacitor values and calculate.

Series Capacitor Formula

When capacitors are connected in series, the reciprocal of the equivalent capacitance is equal to the sum of the reciprocals of the individual capacitances.

1 / Ctotal = 1 / C1 + 1 / C2 + 1 / C3 + ... + 1 / Cn

Ctotal = 1 / (1/C1 + 1/C2 + ... + 1/Cn)

Two-Capacitor Formula

For exactly two capacitors, the equation simplifies to:

Ctotal = (C1 × C2) / (C1 + C2)

How Series Capacitors Work

Capacitors connected in series form a chain between two circuit nodes. In the ideal steady-state model, the magnitude of charge on each capacitor is the same.

The total applied voltage is divided among the capacitors. Because voltage is given by V = Q/C, a smaller capacitance receives a larger voltage for the same charge.

Same Charge

The ideal series model has the same charge magnitude on each capacitor.

Divided Voltage

The supply voltage is distributed among the individual capacitors.

Lower Equivalent C

The equivalent capacitance is always lower than the smallest individual capacitor.

Two Capacitors in Series

For two capacitors, the product-over-sum formula provides a convenient shortcut.

Ctotal = (C1 × C2) / (C1 + C2)

Example: 100 nF and 100 nF

Two equal 100 nF capacitors produce:

Ctotal = (100 × 100) / (100 + 100)

Ctotal = 10000 / 200

Ctotal = 50 nF

Two equal capacitors in series therefore produce an equivalent capacitance equal to half the value of either capacitor.

Voltage Distribution Across Series Capacitors

Since the charge is the same on each capacitor, the voltage across an individual capacitor is:

Vᵢ = Q / Cᵢ

Using the equivalent capacitance:

Q = Ctotal × Vtotal

Vᵢ = Q / Cᵢ

Example: 100 nF + 200 nF at 12 V

First calculate the equivalent capacitance:

Ctotal = (100 × 200) / (100 + 200)

Ctotal = 66.67 nF

Q = 66.67 nF × 12 V

Q ≈ 800 nC

The voltage across the 100 nF capacitor is:

V1 = 800 nC / 100 nF

V1 = 8 V

The voltage across the 200 nF capacitor is:

V2 = 800 nC / 200 nF

V2 = 4 V

The voltages add to the 12 V applied voltage.

Energy Stored in Series Capacitors

The energy stored in an individual capacitor is:

E = 1/2 × C × V²

The total energy stored in the network is the sum of the energy stored in each capacitor:

Etotal = E1 + E2 + E3 + ... + En

For an ideal equivalent capacitor, the same total energy can also be represented by:

Etotal = 1/2 × Ctotal × Vtotal²

Worked Series Capacitor Examples

Example 1: Two 1 µF Capacitors

Two 1 µF capacitors are connected in series across a 12 V supply.

Ctotal = 1 µF / 2

Ctotal = 0.5 µF

Q = 0.5 µF × 12 V

Q = 6 µC

Because the capacitors are equal, each capacitor has 6 V across it.

Example 2: 100 nF + 220 nF

A 100 nF capacitor and a 220 nF capacitor are connected in series across 12 V.

Ctotal = (100 × 220) / (100 + 220)

Ctotal = 68.75 nF

Q = 68.75 nF × 12

Q = 825 nC

The 100 nF capacitor receives approximately 8.25 V, while the 220 nF capacitor receives approximately 3.75 V.

Common Series Capacitor Examples

Capacitors Equivalent Capacitance Applied Voltage Total Charge
100 nF + 100 nF 50 nF 12 V 600 nC
1 µF + 1 µF 500 nF 12 V 6 µC
100 nF + 220 nF 68.75 nF 12 V 825 nC
100 nF + 220 nF + 330 nF ≈53.78 nF 12 V ≈645.4 nC
10 nF + 100 nF + 1 µF ≈9.01 nF 24 V ≈216.2 nC

Applications of Series Capacitors

Series Capacitor Voltage Ratings

Connecting capacitors in series can allow a capacitor network to withstand a higher total voltage than an individual capacitor, but the voltage does not necessarily divide equally.

The voltage division depends on capacitance, leakage current, tolerance, dielectric properties and operating conditions. A smaller capacitance can experience a larger voltage.

Important design consideration
Do not simply add capacitor voltage ratings and assume that each component will share the applied voltage equally. Practical high-voltage series capacitor networks may require balancing resistors or other voltage-sharing arrangements.

Practical Design Notes

  • The equivalent capacitance of positive capacitors in series is lower than the smallest individual capacitor.
  • Capacitors in series carry the same charge magnitude in the ideal steady-state model.
  • Voltage divides inversely with capacitance.
  • Capacitor tolerance affects the actual capacitance and therefore the voltage distribution.
  • Leakage current can affect voltage sharing in real capacitor networks.
  • Electrolytic capacitors require correct polarity and should not be treated like ideal polarity-independent capacitors.
  • For high-voltage series capacitor arrangements, verify individual voltage ratings under worst-case tolerance and leakage conditions.
  • Capacitor ESR, ESL and dielectric behavior can become important at higher frequencies.

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Frequently Asked Questions

How do you calculate capacitors in series?

For capacitors connected in series, calculate the reciprocal of the equivalent capacitance by adding the reciprocals of each capacitor: 1/Ctotal = 1/C1 + 1/C2 + ... + 1/Cn.

What is the formula for two capacitors in series?

For two capacitors in series, the equivalent capacitance is Ctotal = (C1 × C2) / (C1 + C2).

Is series capacitance lower than the smallest capacitor?

Yes. For positive capacitance values connected in series, the equivalent capacitance is lower than the smallest individual capacitor.

What happens to voltage across capacitors in series?

In a series capacitor network, the same charge magnitude appears on each capacitor in the ideal steady-state model. The voltage across each capacitor depends on its capacitance: V = Q/C.

Do capacitors in series have the same charge?

In the ideal series-capacitor model, each capacitor carries the same magnitude of charge.

How is voltage divided between series capacitors?

Because the charge is the same, the voltage across each capacitor is inversely proportional to its capacitance. A smaller capacitor receives a larger voltage.

Why are capacitors connected in series?

Series capacitors can be used to obtain a lower equivalent capacitance and, in some configurations, to increase the effective voltage rating of a capacitor network when voltage sharing is properly controlled.

What is the equivalent capacitance of two equal capacitors in series?

Two equal capacitors connected in series have an equivalent capacitance equal to half the value of either capacitor. For example, two 100 nF capacitors produce 50 nF.

How do you calculate energy stored in a capacitor?

The energy stored in a capacitor is E = 1/2 × C × V², where C is capacitance in farads and V is voltage across the capacitor.